La conclusión de que (2) is not sufficient:
If x=4, that means units digit of (243)^4=1. However, we don't know anything about y. If y is odd, units digits of n can be 3 or 7; if y is even, units digits of n can be 9 or 1. Then, we can only say digit unit of n is odd, but we can have four different values: 3,7,9 or 1, depending on the value of y - 2 is not sufficient
La conclusión de que (1) is sufficient:
We know both x and y can have four possible values each one: 3 (x or y=1), 9 (x or y=2), 7 (x or y=3) and 1 (x or y=4) (the sequence is repeated for lower/higher values of x and y).
If x+y=7, we can have infinite combinations of the pair (x,y):
-2,9
-1,8
0,7
1,6
2,5
etc.
However, this fixes the possible relation between (243)^x and (463)^y! We can see this if we write down the sequence in a wide range of values for x and y:
Power Unit digits
-3 3
-2 9
-1 7
0 1
1 3
2 9
3 7
4 1
5 3
6 9
7 7
8 1
9 3
10 9
If x=-2, y must be equal to 9. In that case, unit digit of n is equal to 7*3=21
We can see every combination of x+y=7 yields a result of 7, so (1) is sufficient.
I hope is clearly explained!!
I took me more than 2 minutes

and my first choice was (3) Together